Created by Stat Modeller

Lean Six Sigma Brown Belt

Welcome to the Exam for "Lean Six Sigma Brown Belt".

Following are the guidelines for the examination. Please read it carefully before starting the exam.

Guidelines:

  1. Duration: 120 minutes
  2. Total 75 MCQs Questions + 5 Scenario Based Questions
  3. For fill in the blank type questions, use 2 decimal points without any symbols like % or anything else.
  4. Write the full name with your company email ID. This name will appear on the certificate.
  5. There is no negative marking.

All the Best!!!
Team Stat Modeller


 

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1. Reduce cycle time but quality drops. Which metric failed?

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2. If DPMO is 3.4, the process sigma level is approximately

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3. Reducing defect rate from 8% to 3% is

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4. A project reduces defect rate by 1% but saves ₹5Cr annually. It should be prioritized based on

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5. Which cost reduces after Six Sigma implementation?

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6. A process produces 25 defects in 5,000 units. Each unit has 4 opportunities. What is DPMO?

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7. Reducing lead time improves customer satisfaction but reduces profit margin. Conflict is between

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8. A project reduces changeover time but increases scrap rate slightly. Which metric failed to be monitored properly?

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9. A problem statement must include which combination?

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10. Goal statement must include baseline and

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11. Goal: “Improve quality significantly.” This lacks

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12. Financial benefit must be validated by

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13. Cycle time = 65 sec while takt time = 50 sec. This indicates

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14. Inventory between processes primarily increases

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15. If Customer Demand = 2400 units/month and available time is 25 working days running 3 shifts each of 8 hours. There are 30 minutes break in each shift. Takt time is

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16. In 10,000 cables, 120 defects are found. Each cable has 4 CTQs. What is DPMO?

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17. 100 defects in 10,000 units, 10 opp each. DPMO?

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18. Observed Variation = Process Variation + _________________

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19. If long-term sigma = 4.5, short-term sigma approx

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20. Sample size = 5 per subgroup, continuous data. Chart?

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21. In normal distribution, area under curve equals

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22. Step yields: 0.98, 0.96, 0.95, 0.97. RTY ≈

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23. Range is sensitive to

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24. For skewed life data, preferred distribution is

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25. Warranty reduction ₹40L/year classified as

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26. Mean = 30, SD = 5. What % of area will be below 40?

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27. Time between cable failures best modeled by

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28. %GRR = 8%, NDC = 6. Measurement system is

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29. If mean = 50, SD = 10, Z for value 70 is

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30. Process A: μ=50, σ=5. Process B: μ=100, σ=8. Higher relative variation?

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31. Points alternating high-low-high-low suggests

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32. 7 points trending upward indicates

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33. In Visial Management, Visual boards improve

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34. Specification limits are based on

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35. Dashboards mainly support

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36. No defined reaction plan increases

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37. When sample size varies and counting defects per unit

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38. 9 consecutive points on one side CL indicates

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39. Counting number of defects per unit (constant sample size)

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40. Monitoring defectives proportion requires

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41. Scatter Plot used to study

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42. Project saves ₹80L/year, 3-year horizon, investment ₹1Cr. Net gain over 3 yrs =

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43. In Regression Analysis, VIF high indicates

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44. Regression equation predicts

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45. Higher RPN indicates

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46. High correlation does not imply

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47. In Regression Analysis, if p-value of slope >0.05, conclusion

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48. When practical significance high but statistical not significant, next step

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49. Severity = 8, Occurrence = 5, Detection = 4. RPN equals

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50. If top 3 causes contribute 75% defects, strategy should

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51. Cp=1.8, Cpk=1.7, process unstable. First action?

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52. Machine A produces 100 units and 12 are failed, Machine B produces 200 units and 10 are failed. If you perform hypothesis test, what will be the decision?

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53. Cp high but Cpk low indicates

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54. Process in control, Cp=1.2, Cpk=1.2. Customer complaints continue. Most likely cause

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55. Mean=200, SD=20. Spec=240. Z =

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56. If detection improved but occurrence high, long-term risk remains due to

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57. Reducing variation supports Lean by

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58. Inventory reduced by ₹2Cr, carrying cost 12%. Annual saving?

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59. In DOE, Main effect measures

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60. Large WIP triangles in VSM indicate

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61. In Full Factorial DOE, 2 factors at 2 levels requires

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62. In SMED, Converting internal to external setup reduces

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63. Main advantage of Fractional Factorial DOE

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64. In DOE 2⁴ Full Factorial, Number of runs required

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65. Kaizen focuses on

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66. If Detection improves from 8 to 3 (S=7, O=5), new RPN =

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67. Best factor combination in DOE selected based on

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68. In Fractional Factorial DOE, 2⁴⁻¹ design requires

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69. Response increases with higher temp but decreases after threshold. This suggests

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70. Takt mismatch across stations causes

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71. Perfection principle in Lean means

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72. Jumping to Improve before validating X’s causes

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73. Skipping Measure and directly analyzing leads to

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74. Lean reduces waste, Six Sigma reduces

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75. Lean without Six Sigma may improve speed but risk